Program: To check given character is Alphabet, Digit or any Other
#include<iostream.h>
#include<conio.h>
//check given character is alphabets, digit or any other character
#include<conio.h>
//check given character is alphabets, digit or any other character
int main()
{
char a;
cout <<"Enter a character : \n";
cin >> a;
if(((a >= 'A') && (a<='Z')) || ((a >='a') && (a <= 'z')))
cout << "You entered an Alphabet\n";
else if(a >= '0' && a <='9')
cout << "You entered a digit\n";
else
cout << "You entered non alpha numeric character\n";
/* i define char a that contain only one character and then i take input
from user. and then i set condition to check what type of data user enter
first condition that i set a >= 'A' && a<='Z' and in these i write two condition]
joining with && now understand the function of && this is used to check that both the condition is
true or false like here i set a>= 'A' && a<='Z' this condition run when both is true
this condition mean that value is between A & Z and now see full condition
that condition i for uppercase now check for lower case we separate condition
with OR sign '||' this mean condition must true either one of the side must true
like here (((a >= 'A') && (a<='Z')) || ((a >='a') && (a <= 'z')))
first uppercase check if it false then it check lower case either one of these
true then only it execute then it print you enter alphabet
Now second condition you can see to check number (a >= '0' && a <='9')
i use else if condition u can also use if condition under else
like else
{
if((a >= '0' && a <='9')
cout<<"You enter Number";
}
like this you can also give its same the above condition check the number
between 0 to 9
and third is else part other than above number or alphabet it execute
that part
*/
getch();
return 0;
}
OUTPUT
thanks a lot
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